The friendly folks at Les Schwab were kind enough to invite me into a shop bay on a quiet day so they could help me take some measurements.
After removing the front-left wheel (my online research concluded that the front brakes are slightly larger than the rear in most cases), measuring from the center of the hub to the outer most portion of the calipers showed 7⅜", which equals a 14¾" diameter. That means a wheel with an inside diameter of 15" or more should work (provided it also meets other criteria for fitment).
I also had the technician measure the hub protrusion, which translates to the center bore hole of a wheel. That measurement is 2.8".
Please keep in mind my KJ is a 2005 Limited. I don't know if these measurements would be different on other models or years of KJs.
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The reason these measurements were important to me is because I found a type of wheel that I really like. There are 2 basic styles of this type, but only one comes in a 16x7 5/4.5 4"bs. Unfortunately, that wheel only has an inside diameter of 13.47". However, that same style also comes in a 17" wheel - 17x7 5/4.5... but with a 4.5" backspace. It has an inside diameter of 15.4", so it should fit over the disk brakes and calipers of a KJ.
Questions for those of you with experience:
- Will a 17x7 5/4.5 4.5"bs wheel work without using a half-inch spacer?
- And if so, what is the largest tire that would fit on a 3" lifted KJ?
- Finally, if a half-inch spacer would be necessary to prevent the tires (and maybe even the wheel itself) from scraping the suspension components or inside body parts, is that small a spacer such a bad thing?
Thanks for your guidance.